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abhishek kumar Grade:
        

xsin^2x

4 years ago

Answers : (2)

Panga Mahita
37 Points
										

Is it sin2x or sin2x?? Plz tell so that I can reply u.

4 years ago
Manpreet Raj
29 Points
										

Abhishek Kumar,


u need to do this by using integration by parts.


u must be knowing the ILATE rule.


so, taking x as the 1st function and sin^2x as the 2nd function,


integrate it by using the formula :


integration uv dx = u ( integration v dx) - integration { (du/dx) integration v dx} dx


the answer will come out as :


( x/2 - sin4x/8 ) ( x-1)


post ur feedback


thanks

4 years ago
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