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				   plz anybody tell me that how can i get good rank in iit jee
				   

4 years ago

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Answers : (1)

										

no need to take tensn buddy just work hard coz,..............hardwork conquers all.

4 years ago

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I will be appearing for IITJEE-2016. I am very good at the concepts. But I am too slow. Any suggestions? How can I improve my speed?
 
 
Dear student, Please try to solve as many as questions as possible. By this definetly your speed will increase. Thanks.
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Vijay Mukati 7 months ago
 
Stay focused on your studies and keep in mind that one must focus on Physics, Chem and Maths, try to fortify these three, take some coaching classes from a reputed place like Akash Inst...
 
Ayushmaan Vardhan 7 months ago
 
the only way to improve your speed is by lots of practice and have one thing in mind and never think that your concepts are strong ther are many students whose concepts are upto msc level...
 
Prajwal Kavad 7 months ago
Hello Sir, how can i preapare for Jee mains 2016 to score max. marks as i have wasted my whole 11 th class as well as summer vacation and now i m getting frustated... please help me as i...
 
 
beta tum ye batao ki tum kya koi coaching jaate ho agar haan to wahan us course ko jion karo jo 11 aur 12 ka syllabus ek saal mein karate ho jahaan tak books ka sawal hai jee main ke liye...
 
rohan 5 months ago
 
FIRST YOU SOLVE ALL BASIC CONCEPT QUESTIONS AND THEN YOU SOLVE HIGHER LEVEL QUESTIONS FOR EXAMPLE FIRST YOU PREFER USS-1 AND USS-2 BOOKS AND THEN SOLVE DC PANDEY,ANURAG MISHRA,CENGAGE...
 
Mitesh Rathi Classes 5 months ago
 
@rohan Sir me aisi koi coaching nhi jta...Only self-study pe dependent hun....And R.D. sharma objective or sirf board vaali....
 
Sankalp Tiwari 5 months ago
find the equation of the line passing through point (-1,-2) and is parallel to the line joining the points a(3,4) and b(7,8).
 
 
m=y2-y1/x2-x1 m=1=tan 45’ m=8-4/7-3=1 y-y1=m(x-x1) y+2=(1)(x+1) so, the equation is x-y-1=0
 
sneha 5 months ago
 
i need the steps please
 
sneha 5 months ago
 
x-y-1=0
 
jawwad 5 months ago
What is Ajax and why it is used widely?
 
 
AJAX Uses HTTP Requests In traditional JavaScript coding, if you want to get any information from a database or a file on the server, or send user information to a server, you will have to...
 
Ravi Sharma 6 years ago
 
AJAX = Asynchronous JavaScript and XML AJAX stands for Asynchronous JavaScript And XML. AJAX is a type of programming made popular in 2005 by Google (with Google Suggest). AJAX is not a new ...
 
Himanshu Vijay 6 years ago
sir, are the opening and closing ranks general ranks or category ranks
 
 
It is available on the official website of jee.
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Vijay Mukati 7 months ago
 
are the ranks given according to category
 
gsjkiran 7 months ago
prove that (1²×2²÷1!)+(2²×3²÷3!)+--- = 27e
 
 
I think that is wrong... And plz continue the equation for a little more next time Thanks Mohammed Askiitans Student
 
MOHAMMED ANAS one year ago
 
n^4/n!+n^2/n!+2(n^3/n!) =15e+2e+2(5e)=27e
 
vamshiakena one year ago
 
n^4/n!+n^2/n!+2(n^3/n!) =15e+2e+2(5e)=27e
 
vamshiakena one year ago
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  • Complete JEE Main/Advanced Course and Test Series
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