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will iitjee 2013 be there?????

3 years ago

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sir i got 466 in boards and 210 in mains ,but flunked advanced should i join nit or write jee next year (obc)
 
 
Getting into NIT without Advance is not possible, dropping a year may not be a good choice..wel its up to you...you can try securing a place for admission at one of the esteemed...
 
Frank Defeo 11 hours ago
 
i think that u must take admission in nit or other govt college like dce or nsit as ur board percentage is 93.2 , u will definitely get a good college with desired atream and while doing ur...
 
ng29 11 hours ago
Hi, I need advise on your self study materials for IIT Jee examination.
 
 
For IIT JEE, you must be concptually sound. In order to achieve that, it is important to expose yourself to some of the excellent books on Physics, Chemistry and Mathematics. These are some...
 
Mihir 10 days ago
 
h.c.verma’s phy’s books ,,r.d. sharma’s math books,,,,,o.p.tandan‘s chy’ books are referable
 
SAITEJA GOUD 9 days ago
Hi, I’m aiming b/w 3500 to 4000 rank in jee advanced. Can someone tell me the required books and material needed for this rank. Also, is HC Verma enough for this rank?
 
 
yap . But H.C.Verma is nice book . See if you can get Haliday,Resnick,Walker. For Maths, books of Asit Das Gupta and R.D.Sharma are best .
 
Piku 9 months ago
 
Firstly ur basics need to be strong. You can practice from H C Verma. If your concepts and basics are clear then u can refer I.E.Irodov.
 
MAlav Shah 9 months ago
 
its better to carry even (pc.agarwal) book with you, for other subjects just give more preference to arihant series or cengage series
 
dheeraj 9 months ago
i am talking about revision notes given at the website
 
 
These are not enough, you must look at the book also....
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Saurabh Kumar 29 days ago
prove that (1²×2²÷1!)+(2²×3²÷3!)+--- = 27e
 
 
I think that is wrong... And plz continue the equation for a little more next time Thanks Mohammed Askiitans Student
 
MOHAMMED ANAS 5 months ago
 
n^4/n!+n^2/n!+2(n^3/n!) =15e+2e+2(5e)=27e
 
vamshiakena 5 months ago
 
n^4/n!+n^2/n!+2(n^3/n!) =15e+2e+2(5e)=27e
 
vamshiakena 5 months ago
how rank is required for getting admission in IIT ropar
 
 
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Saurabh Kumar one month ago
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