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```				   The coefficient of t24 in (1+t²)12(1+t12)(1+24) is
```

5 years ago

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```										gud question hemant ....
please check the solution of it
Multiplying the last two expressions we have to find coefficient of t24in (1+t²)12(1+t12+24) t24 term will come as a sum of three terms in the expanded expression1st term is t24 term in 1st expression multiplied by 1 in the second expression.2nd term is t12 term in 1st expression multiplied by t12 term in the second expression.3rd term is 1 in the first expression multiplied by t24 term in the second expression.Coefficients of 1 and 3 terms are 1 and 1.Coefficient of 2 term = coefficient t12 term in 1 st expression which is (1+t²)127th term or 6+1th term in the expansion will have t12 termHence coefficient of 7th term = 12C6Therefore coefficient of t24 term will be12C6 + 2 ...Answer...
i think we are at solutions....
```
5 years ago

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