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how we can find incentre if the incircle is made by x,y axis and a line having intercepts a and b as  a/x+b/y = 1.

4 years ago

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Dear student,


given equation has intercept a and b. The angular bisector of O is y=x


the angular bisector of of other vertex has slope equal to tan(180 - (1/2)tan^-1 (b/a)) let us call this as m


and this passes through a,0 and equation is y = mx - ma


put x=y in the equation


=> incentre = x,y = -ma/1-m,-ma/1-m

4 years ago

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