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				   i have scored 163 i have reservation in OBC so how much rank i can expect in obc and all india  
				   

6 years ago

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Answers : (1)

										

Hi,


Minimum Qualifying Mark for Ranking (MQMR) and Aggregate Cut-off



















































Merit List



MQMR


Aggregate Cut-off
(out of 480)



Chemistry (out of 160)



Mathematics
(out of 160)



Physics
(out of 160)



General (CML)



11


11


8


178


OBC


10


10


8


161


SC


6


6


4


89


ST


6


6


4


89


PD


6


6


4


89


For IIT JEE cut-off details you can visit the following:

http://www.askiitians.com/IIT-JEE-2010-Cut-Offs.aspx

http://www.askiitians.com/iits-2009-2010-opening-and-closing-rank.aspx

and for cutoff in new IITs  check the link

http://jee.iitd.ac.in/openclose09.htm    (this link includes the more detail analysis)

for code of the cources check the councelling broucher 2009.


Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best.


 

6 years ago

Post Your Answer

Hi, Which online test series would you consider the best for preparing for JEE? Thanks.
 
 
I think, askiitians would be the best one, because, its the only one that offers such an online programme at a cost of online test series.. you must discuss it with askiitians faculty..
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Saurabh Kumar 10 months ago
 
You can enroll for online coaching on askiitians website http://www.askiitians.com/iit-jee/online-coaching/
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Avinash 10 months ago
 
if you are good in concepts then i will prefer resonance................
 
arsalan nazim 10 months ago
What is the best book for concepts in physics?
 
 
you can get the solutions of HC Verma book on this youtube channel named “Omega Open Course”
 
Sundar Chacha 8 months ago
 
hc verma best physics concept book really ive tried it just blindly follow it
 
purva gupta 9 months ago
find the equation of the line passing through point (-1,-2) and is parallel to the line joining the points a(3,4) and b(7,8).
 
 
m=y2-y1/x2-x1 m=1=tan 45’ m=8-4/7-3=1 y-y1=m(x-x1) y+2=(1)(x+1) so, the equation is x-y-1=0
 
sneha 9 months ago
 
i need the steps please
 
sneha 9 months ago
 
x-y-1=0
 
jawwad 9 months ago
IN CHEMSTRY, PHYSICS,MATHEMATICS
 
 
Hello Student, Pls post full question again
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Nishant Vora one year ago
 
just work hard in all three . Hit approve if u got even a little help by my answer :) Thanks .
 
Drake one year ago
 
Read Aman Goel’s blog. It is a huge help to aspirants like us!
 
RON one year ago
I have heard a lot about UPES- Dehradun and its courses? How is the faculty for Btech CSE courses in UPES?
 
 
Its a good one. They collaborated wid IBM providing better scope to cse students.
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Avinash 10 months ago
 
Hello Mamta, UPES CSE courses is that its courses are in collaboration with IBM, which is rare to find in any Indian university. If you check their official FB page, you can have a sneak...
 
Suchitra Ray 10 months ago
 
Hi Mamta, I agree with Suchitra and Avinash. UPES is one of the best universities in India which is offering engineering courses. I would suggest you to check out their website for details...
 
Devik Aggarwal 9 months ago
sir i want you to make my time table for whole day my school hour are 8 hour and tution hour are 4 hour at night 6 to 10
 
 
I will assume that your school gets over by 2pm. 3:00 – 3:45 – Physics 4:00 – 4:45 – Mathematics 5:00 – 5:45 – Chemistry I know that it is difficult to manage but you have to do it. Good...
 
Anoopam Mishra 9 months ago
 
but i can wake up at night also so can u plz help me for night work
 
jatin garg 9 months ago
 
Till when can you wake up? I will help you manage your time.
 
Anoopam Mishra 9 months ago
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  • Complete JEE Main/Advanced Course and Test Series
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USE CODE: int40

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