Free JEE Adv 2013 solutions
iit jee paper I question no 21 code 7 the answer given by some is 0 while others gave it as 8. kindly explain .
Based on VSEPR theory, the number of 90 degree F-Br-F angles in BrF, is
The structure of BrF5 is square pyramidal. The number of FBrF angles having the value of 90º is eight (8).
but Due to trivial distortion, however, the bond angles (F—Br—F) are slightly less than 90º(85º).
so this question has slight confusion.
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