Equation of motion of a projectile is equals to 12 x minus 3 by 4 x square given that g equals to 10 M per second square what is the range of the projectile (the origin is the point of projection and success is horizontal and y axis is vertical)

Question

Vikas TU · Answer

Dear Student,

R would be the x co-ordinate of the particle when it crosses the x axis after its motion.

the projectile would cross the x-axis once when the co-ordinatesn are (x,0)

y=0
Given is y=(12x-3)/4x2
=>x=1/4 m.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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Equation of motion of a projectile is equals to 12 x minus 3 by 4 x square given that g equals to 10 M per second square what is the range of the projectile (the origin is the point of projection and success is horizontal and y axis is vertical)

Equation of motion of a projectile is equals to 12 x minus 3 by 4 x square given that g equals to 10 M per second square what is the range of the projectile (the origin is the point of projection and success is horizontal and y axis is vertical)

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Equation of motion of a projectile is equals to 12 x minus 3 by 4 x square given that g equals to 10 M per second square what is the range of the projectile (the origin is the point of projection and success is horizontal and y axis is vertical)

Equation of motion of a projectile is equals to 12 x minus 3 by 4 x square given that g equals to 10 M per second square what is the range of the projectile (the origin is the point of projection and success is horizontal and y axis is vertical)

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