a body of velocity-2 kmph strikes ground from height h .another body of same mass from same height with initial velocity 4 kmph is thrown down .final v of 2nd body?

Question

Ritika Bagokar · Answer

h=2t+1/2gt^2 & h=4t+1/2t^2 equate the two equations to get t=2sec put in either of equations to get h ie h=16 use v^2=u^2+2gh v=√4^2 +2g*16 =√336=18.33 hence ans i 18.33

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a body of velocity-2 kmph strikes ground from height h .another body of same mass from same height with initial velocity 4 kmph is thrown down .final v of 2nd body?

a body of velocity-2 kmph strikes ground from height h .another body of same mass from same height with initial velocity 4 kmph is thrown down .final v of 2nd body?

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a body of velocity-2 kmph strikes ground from height h .another body of same mass from same height with initial velocity 4 kmph is thrown down .final v of 2nd body?

a body of velocity-2 kmph strikes ground from height h .another body of same mass from same height with initial velocity 4 kmph is thrown down .final v of 2nd body?

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