A body of mass 10kg moves with a constant velocity of 10m/sec now a constant force acts for 4 s on body n gives it a speed of 2 m/s in the opposite direction. The impulse imparated to the object is

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Vikas TU · Answer

Impulse is given as the change in momentum of the system. Therfore, J = m(vf – vi) => 10*(10-2 – 10) = > -20 Kg-m/s

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A body of mass 10kg moves with a constant velocity of 10m/sec now a constant force acts for 4 s on body n gives it a speed of 2 m/s in the opposite direction. The impulse imparated to the object is

A body of mass 10kg moves with a constant velocity of 10m/sec now a constant force acts for 4 s on body n gives it a speed of 2 m/s in the opposite direction. The impulse imparated to the object is

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A body of mass 10kg moves with a constant velocity of 10m/sec now a constant force acts for 4 s on body n gives it a speed of 2 m/s in the opposite direction. The impulse imparated to the object is

A body of mass 10kg moves with a constant velocity of 10m/sec now a constant force acts for 4 s on body n gives it a speed of 2 m/s in the opposite direction. The impulse imparated to the object is

1 Answers

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