A blind person after walking 10 steps in one direction each of length 80 cm gums randomly to the left or to the right 90 . After walking a total of 40 steps the maximum possible displacement of the person from his starting position could be

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Saswat Pani · Answer

The blind person takes 10 steps each of 80cm which is 8mThen 40steps to left or right which is 32cmThe displacement is the hypotenus of the triangle formed where 8cm is the base nd 32 the heightHence the displacement is√ 32^2+8^2 Which is 32.984

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A blind person after walking 10 steps in one direction each of length 80 cm gums randomly to the left or to the right 90 . After walking a total of 40 steps the maximum possible displacement of the person from his starting position could be

A blind person after walking 10 steps in one direction each of length 80 cm gums randomly to the left or to the right 90 . After walking a total of 40 steps the maximum possible displacement of the person from his starting position could be

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A blind person after walking 10 steps in one direction each of length 80 cm gums randomly to the left or to the right 90 . After walking a total of 40 steps the maximum possible displacement of the person from his starting position could be

A blind person after walking 10 steps in one direction each of length 80 cm gums randomly to the left or to the right 90 . After walking a total of 40 steps the maximum possible displacement of the person from his starting position could be

1 Answers

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Other Related Questions on General Physics

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