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Omkar ajit Darekar Grade: 9
        

a tube well pumps 2400 kg/mins .if the water is coming out with velocity 3m/s.what is the power of the pump?

7 years ago

Answers : (2)

Ramesh V
70 Points
										

power =  force* velocity


force exerted on water in 1 sec = F = m*(v/t)


                                                   =(2400/60)*(3/1) = 120 N


power exerted = F*v=120*3=360 W


--


regards


Ramesh

7 years ago
Harish
13 Points
										Mass of water pumped out per sec = 2400/60 = 40 kg/sPower of pump = kinetic energy of water coming out per sec = mv^2/2 = 180 J Harish kaswan
										
one month ago
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