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Omkar ajit Darekar Grade: 9
`        a tube well pumps 2400 kg/mins .if the water is coming out with velocity 3m/s.what is the power of the pump?`
7 years ago

## Answers : (2)

Ramesh V
70 Points
```										power =  force* velocity
force exerted on water in 1 sec = F = m*(v/t)
=(2400/60)*(3/1) = 120 N
power exerted = F*v=120*3=360 W
--
regards
Ramesh
```
7 years ago
Harish
13 Points
```										Mass of water pumped out per sec = 2400/60 = 40 kg/sPower of pump = kinetic energy of water coming out per sec = mv^2/2 = 180 J Harish kaswan
```
one month ago
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