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as from the wuation. it says bullet loses (10)-1/2 of velocity upon penetration into each plank
I feel that this data is not enough. A lot more data is required like
we need to know the minimum velocity required to pass through a single plank.??
how far away are you shooting? how thick are the planks? how far apart are the planks?
definitely not enough info to answer. but technically the least that COULD stop it if the variables are right is 2 or 3.
Let thickness of one plank be = d.
KE1 = 0.5*m*v2
KE2 = 0.5*m*v 22 = 0.9 *0.5*m*v2 So, v 22 = 0.9 *v2 .
Let us calculate deceleration produced by one plank using v 22 = v 12 - 2*a*d
So, 2*a = (0.1*v2) / (d).
Final velocity = 0 m/s.
So, 0 = v 2 - 2*a*d1
d1 = v 2 / (2*a) = v 2 / ((0.1*v2) / (d)) = 10*d.
So,
d1 = 10*d.
Since one Plank is of thickness d, 10*d is thickness of 10 planks.
So, 10 planks are required just to stop the bullet.
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