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Vishrant Vasavada Grade: 11
        Two resistors R1 = 600 +- 3 Ohm and R2 = 300 +- 6 Ohm are connected in series combination. Find the percentage error in net resistance.
7 years ago

Answers : (1)

AskIITians Expert Hari Shankar IITD
17 Points
										

Net resistance R = R1 + R2


(In a series combination, resistances get added)


Max error in measurement of R1 = 3 ohm.


Relative error = Max. error/Measured value


Therefore,


Relative error for R1 = 3/600 = 0.005


Max error in measurement of R2 = 6 ohm.


Relative error for R2 = 6/300 = 0.02


When two quantities are added, the respective errors involved also get added.


R = R1 + R2


Measured value of R = 600 + 300 = 900 ohms


Error in measuring R = 3 + 6 = 9 ohm


Relative Error in measurement of R = 9/900 = 0.01


Percentage error = Relative error * 100


or, Percentage error = 0.01* 100


or, Percentage error in measuring R = 1 %


 




7 years ago
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