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Amit Tapas Grade: 10
        

A body covers 200cm in first 2 sec and 220 cm in next 4sec .what is the velocity after 7(th)  second.

6 years ago

Answers : (3)

vikas askiitian expert
510 Points
										

let initial velocity = u & accleration is a then


distance travelled in 4 sec = S6


using , s=ut + at2/2


          S6 = 4u + a36/2


               =  6u+18a


distance covered in 2 sec = S2 = 2u + 4a/2


                                           =2u+2a = 200           (given)


                                       u+a = 100             ........................1


now distance covered in 2 to 6 sec is given 220cm


      S6-200 = 220


     6u + 18a = 420       


        u+3a = 70             .................2


from 1& 2


a = -15 & u=115


velocity after 7 sec = V7


       V7 = u + at


           =115 - 15*7=10cm/sec

6 years ago
Aniket Patra
48 Points
										

Let the initial velocity be u and the accelaration be f.For the motion of 200cm we have 200=u+1/2f(2)^2 and for 220cm we have 220=u+1/2f(6)^2..Solve those two equations and get the values of u and f..Then for distance covered in 7th sec apply the formula s=u+1/2f(2t-1).

6 years ago
Srijan Debnath
26 Points
										
A stone is dropped from a height of 19.6 m what is the time taken by the stone to travel the metre of the path
 
one year ago
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