MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
ABHISHEK VASHIST Grade: 12th pass
        

Q.Two pistons of hydraulic press have diameter of 30cm and 2.5cm.


Find the force exerted by the longer piston when 50kg wt is placed on smaller piston.If the stroke of the smaller piston is 4cm, find the distance through which the longer piston would move after 10 strokes

6 years ago

Answers : (2)

Vijay Luxmi Askiitiansexpert
357 Points
										

Hi,


 


Please don't post the same question twice..

6 years ago
Chetan Mandayam Nayakar
312 Points
										

ratio of forces =(30/2.5)2=144, force exerted by larger piston=50*144=7200kg wt


larger piston will move a distance= 4*10/144=5/18=0.27cm

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 6,837 off
USE CODE: JYOTI
  • Kinematics & Rotational Motion
  • OFFERED PRICE: Rs. 636
  • View Details
Get extra Rs. 273 off
USE CODE: JYOTI

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details