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Akhilesh Gandhi Grade: 11
        

if in atwood machine m1=1.30kg and m2=2.80kg at t=o.


m1 starts losing the mass at a rate of .200kg/s due to leakage.at what rate does the acc. of the container  changes at t=0sec and t=3 sec.


when dos the acc. reach max. value

7 years ago

Answers : (2)

rahul bajaj
31 Points
										

what is an atwood machine.

7 years ago
vikas askiitian expert
510 Points
										

dm1/dt = -0.2kg/s           ( given)


dm1 = -0.2dt


integrating both sides


m1 = -0.2t + c


at t=0 , m1=1.3


therefore  ,  c=1.3


now , m1 = 1.3 - 0.2t ...............1                                      (mass of m1 at any time)


now accleration (a)= g(m2-m1)/(m2+m1)


     a = g{m2 - (1.3-0.2t)}/{m2+(1.3-0.2t)}                        (putting m1 from eq 1)


    a =g(1.5+0.2t)/(4.1-0.2t)           ...................2              (after putting value of m2)


 da/dt = g(1.12)/{4.1-0.2t)2  ................3


at t=0 ,


da/dt = 0.652m/s2


at t=3


da/dt = 0.896m/s2


 


 


 

7 years ago
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