Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Akhilesh Gandhi Grade: 11
```        if in atwood machine m1=1.30kg and m2=2.80kg at t=o.
m1 starts losing the mass at a rate of .200kg/s due to leakage.at what rate does the acc. of the container  changes at t=0sec and t=3 sec.
when dos the acc. reach max. value```
7 years ago

## Answers : (2)

rahul bajaj
31 Points
```										what is an atwood machine.
```
7 years ago
510 Points
```										dm1/dt = -0.2kg/s           ( given)
dm1 = -0.2dt
integrating both sides
m1 = -0.2t + c
at t=0 , m1=1.3
therefore  ,  c=1.3
now , m1 = 1.3 - 0.2t ...............1                                      (mass of m1 at any time)
now accleration (a)= g(m2-m1)/(m2+m1)
a = g{m2 - (1.3-0.2t)}/{m2+(1.3-0.2t)}                        (putting m1 from eq 1)
a =g(1.5+0.2t)/(4.1-0.2t)           ...................2              (after putting value of m2)
da/dt = g(1.12)/{4.1-0.2t)2  ................3
at t=0 ,
da/dt = 0.652m/s2
at t=3
da/dt = 0.896m/s2

```
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on General Physics

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 1,272 off
USE CODE: Neerajwin
• Kinematics & Rotational Motion
• OFFERED PRICE: Rs. 636
• View Details
Get extra Rs. 51 off
USE CODE: Neerajwin