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Deepak Sharma Grade: 11
        8. A weight is attached to the free end of a sonometer wire. It gives resonance at a length 40 cm when it is

resonanced with a tuning fork of frequency 512. The weight is then immersed wholly in water, the resonant
length is reduced to 30 cm. The relative density in which weight suspended is
(A) 16/9 (B) 16/7 (C) 16/5 (D) 16/3
6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

v(frequency) is proportional to W1/2 /lamda


so for constant frequency , lamda proportional to W1/2                 (lamda is wavelength)


so, (lamda)1/(lamda)2  =  (W1/W2)1/2 


      L1/L2 = (W1/W2)1/2


W1 = DVg ,W2 = DVg -DwVg  &   L1 = 40 ,L2 =30           (D is dencity of material and Dw is dencity of water)


   now ,


            40/30 = (DVg/DVg - DwVG)1/2


          D/Dw = 16/7

6 years ago
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