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`        A projectile is thrown in the upward direction making an angle of 60  with the horizontal direction with a velocity  of 147 m/s. Then what is the time after which its inclination with the horizontal is 45 ?`
7 years ago

510 Points
```										 let after time t its inclination with horizontal is 45
at this time Vy /Vx =tan45  or Vy =Vx
Vx remains constant =147cos60 =Vy
now using equation of motion for verticle direction
Vy=Uy-gt..........eq1
Uy=147sin60 ,Uy=147cos60
putting in eq 1,
t=5.36 sec

```
7 years ago
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