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```				   a mass of 4 kg rests on a horizontal plane the plane. the  gradually inclined until at an angle 15 with the horizontal, the mass just bugins to slide. what is the cofficient of static friction between the block and the surface?
```

6 years ago

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### Answers : (3)

```										 M = 4 kg
x= theta =  15
Mgsinx = μMgcosx
then find μ = ?  if u find worng ans then tell me
```
6 years ago
```										Dear Vinay,
This is called angle of repose. http://www.askiitians.com/iit-jee-physics/mechanics/friction-page4.aspxhttp://www.askiitians.com/iit-jee-physics/mechanics/friction-page5.aspxSo coefficient of static friction = ms = tan(α) = tan(15°)Please feel free to post as many doubts on our discussion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly.We are all IITians and here to help you in your IIT JEE preparation.All the best.Regards,Askiitians Experts,Gokul  Joshi
```
6 years ago
```										A car of mass 1000 kg travelling at 32 m\s dashes into the rear of a truck of mass 8000 kg moving in the same direction with a velocity of 4 m\s after the collision the car bounces with a velocity of 8 m\s what is the velocity of truck after the impact
```
2 months ago

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