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• Kinematics & Rotational Motion
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```				   Two radioactive sources A and B initially contian equal nno. of radioactive atoms. Source A has t½ of 1 hour and source B has t½ 2 hours. What is the ratio of rate of disintegration of A to B
i)initially
ii)after 2 hours
iii)after 10 hours
What is the method to do these questions?????
```

6 years ago

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```										Radio active decay follows first order kinetics.
So, rate of decay is given by Rate = k [N0 (1/2/)n]  where k is decay constant. k =0.693/ t1/2 ; n is number of half-lives.
(i) Initially, n=0
So, Rate -1 = (0.693/ 1) N0  and  Rate-2 = (0.693/ 2) N0
Or (Rate-1 / Rate-2 ) = 2
(ii) After 2 Hours
2 Hours is 2 half lives for for A and 1 Half life for B
Rate -1 = (0.693/ 1) N0 (1/2)2 and  Rate-2 = (0.693/ 2) N0 (1/2)1
(Rate-1 / Rate-2 ) = 1
(iii) After 10 Hours
10 Hours is 10 half lives for for A and 5Half life for B
Rate -1 = (0.693/ 1) N0 (1/2)10 and  Rate-2 = (0.693/ 2) N0 (1/2)5
(Rate-1 / Rate-2 ) = 0.0625
```
6 years ago

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