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Mohamed Faisal Grade: 11
        

Two radioactive sources A and B initially contian equal nno. of radioactive atoms. Source A has t½ of 1 hour and source B has t½ 2 hours. What is the ratio of rate of disintegration of A to B


i)initially


ii)after 2 hours


iii)after 10 hours


What is the method to do these questions?????

7 years ago

Answers : (1)

Srinivas Rao
11 Points
										

Radio active decay follows first order kinetics.


So, rate of decay is given by Rate = k [N0 (1/2/)n]  where k is decay constant. k =0.693/ t1/2 ; n is number of half-lives.


(i) Initially, n=0


So, Rate -1 = (0.693/ 1) N0  and  Rate-2 = (0.693/ 2) N0 


Or (Rate-1 / Rate-2 ) = 2


(ii) After 2 Hours


2 Hours is 2 half lives for for A and 1 Half life for B


Rate -1 = (0.693/ 1) N0 (1/2)2 and  Rate-2 = (0.693/ 2) N0 (1/2)1


(Rate-1 / Rate-2 ) = 1


(iii) After 10 Hours


10 Hours is 10 half lives for for A and 5Half life for B


Rate -1 = (0.693/ 1) N0 (1/2)10 and  Rate-2 = (0.693/ 2) N0 (1/2)5


(Rate-1 / Rate-2 ) = 0.0625

7 years ago
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