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pallavi pradeep bhardwaj Grade: 12
        

A totl charge Q is broken in two parths Q1 and Q2 and they are placed at a distance R from each other the maximum force of repulsion between them will occur when

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear pallavi


 let parts are sepereted at a distance of d


Q=q1+q2 (conservation of charge)


so repulsion force F= k Q1(Q2)/d2


                                      k Q1(Q-Q1)/d2


     here Q and d are constant so for maximum force differentiate the force w.r.t Q1


 dF/dQ1 = k/d2 [Q -2Q1]


 for maximum force dF/dQ1=0


                             Q-2Q1=0


                              Q1 +Q2 -2Q1 =0


                             Q1 =Q2


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Badiuddin

7 years ago
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