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Two spherical conductors B and C having equal radii and carrying equal charges on them repel each other with a force F when kept apart at some distance A third spherical conductor having same radius as that of B then brought in contact with C and finally removed away from both The new force of repulsion between B and C is
Dear pallavi
when 2 identicle metalic surface bought in contact then charge onn them are equalised due to the flow of free elctron
let the initial charge on B and C is q
when third sphere come in contact with B then new charge on B =q/2
and charge on the third conductor =q/2
and third conductor come in contact with C so total charge =q/2 + q =3q/2
charge will equally distribute ,so charge on C = 3q/4
now force = k (q/2)(3q/4) /d2
= 3F/8
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