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sneha sunil raikar Grade: 12
        a thin half ring of radius R=20cm is uniformly charged with a total charge q=0.70mC.find the magnitude of electric field strength at the centre of curvature of this half ring
8 years ago

Answers : (1)

askiitian expert akshay singh
8 Points
										

hi sneha,


  charge per unit length, λ=total charge/half the circumference


after an angle @ cut an element of length rd@,


therefore,charge dq= λrd@


now elec field due to this element is dE=kdq/r2


the cos @ component of dE will be cancelled and sin @ component will add  up


therefore total elec field=2dEsin @


this expression can be integrated from @=0 to pi/2 to get the desired answer


 

8 years ago
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