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sunil suthar Grade: Upto college level
        Explain why the work needed to move a particle with charge Q through a potential differenceΔV is W = QΔV, whereas the energy stored in a charged capacitor is U =1/2QΔV. Where does  the ½ factor come from?
7 years ago

SAGAR SINGH - IIT DELHI
879 Points
										Dear sunil,
Work must be done by an external influence to "move" charge between the  conductors in a capacitor. When the external influence is removed the  charge separation persists in the electric field and energy is stored to  be released when the charge is allowed to return to its equilibrium position. The work done in establishing the electric field, and hence the amount of energy stored, is given by:

$W= \int_{q=0}^Q V \text{d}q = \int_{q=0}^Q \frac{q}{C} \text{d}q = {1 \over 2} {Q^2 \over C} = {1 \over 2} C V^2 = {1 \over 2} VQ.$
We are all  IITians and here to help you in your IIT  JEE preparation.  All the best.

Sagar Singh
B.Tech IIT Delhi
sagarsingh24.iitd@gmail.com


7 years ago
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