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```				   This question is for aspirants:
The electric field strength depends only  on the x and y coordinates according to the law

where a is  a constant, i and j are unit vectors  along x and y axes respectively. Find the flux of the  vector E through a sphere of radius R with its  centre at the origin of coordinates.
its a simple problem.

```

6 years ago

Share

```										 respected sir

i m little confused about this question. actually electric field is 2-d only but for anwsering flux we have to consider total surface area.

well i am presenting my solution:;

E at (R,0,0) is a/R. similarly E at (0,R,0) is also a/R. so this could be taken as the a simple charge system such that a charge q is placed at origin.

now
kq/R^2 =a/R
thus q=1/k* a*R
so flux is 4pi*a*R.
i am not sure this is right . if u find it wrong plz correct it.
```
6 years ago
```										pleeeez tell d answer b'coz the answer coming is radius or size dependent which is not possible
```
6 years ago

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