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Rahul askIITiansExpert.IITR Grade: Upto college level
        

This question is for aspirants:

The electric field strength depends only on the x and y coordinates according to the law

   



            



 



where a is a constant, i and j are unit vectors along x and y axes respectively. Find the flux of the vector E through a sphere of radius R with its centre at the origin of coordinates.

its a simple problem.

7 years ago

Answers : (2)

aman walia
24 Points
										

 respected sir


 


 i m little confused about this question. actually electric field is 2-d only but for anwsering flux we have to consider total surface area.


 


well i am presenting my solution:;


 


E at (R,0,0) is a/R. similarly E at (0,R,0) is also a/R. so this could be taken as the a simple charge system such that a charge q is placed at origin.


 


now


kq/R^2 =a/R


thus q=1/k* a*R


so flux is 4pi*a*R.


i am not sure this is right . if u find it wrong plz correct it.

7 years ago
Akash Verma
36 Points
										

pleeeez tell d answer b'coz the answer coming is radius or size dependent which is not possible

7 years ago
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