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`         Find the total heat produced in the loop of the previous problem during the interval 0 to 30 s if the resistance of the loop is 4.5 mΩ. `
3 years ago

Jitender Pal
365 Points
```										Sol. As heat produced is a scalar prop.
So, net heat produced = H base a + H base b + H base c + H base d
R = 4.5 mΩ = 4.5 ×10–3 Ω
a) e = 3 × 10^–4 V
i = e/R = 3x 10^-4 / 4.5 x 10^-3 = 6.7 x 10^-2 Amp.
H base a = (6.7 ×10^–2)^2 × 4.5 × 10^–3 × 5
H base b = H base d = 0 [since emf is induced for 5 sec]
H base c = (6.7 ×10^–2)^2 × 4.5 × 10^–3 × 5
So Total heat = H base a + H base c
= 2 × (6.7 ×10^–2)^2 × 4.5 × 10^–3 × 5 = 2 × 10^–4 J.

```
3 years ago
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