MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Radhika Batra Grade: 11
        A uniform wire of resistance 100 Ω is melted and recast in a wire of length double that of the original. What would be the resistance of the wire?
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										Sol. ℓ ‘ = 2 ℓ

volume of the wire remains constant.
A ℓ = A’ ℓ ‘
⇒ A ℓ = A’ * 2 ℓ
⇒ A’ = A/2
f = Specific resistance
R = fℓ/A : R’ = fℓ’/A’
100 Ω = f2ℓ/A / 2 = 4fℓ/A = 4R
⇒ 4 * 100 Ω = 400 Ω
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,000
  • View Details
  • Electricity and Magnetism
  • OFFERED PRICE: Rs. 1,600
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details