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Amit Saxena Grade: upto college level
        A capacitor of capacitance 8.0 μF is connected to a battery of emf 6.0 V through a resistance of 24 Ω. Find the current in the circuit (a) just after the connections are made and (b) one time constant after the connections are made.
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										Sol. C = 8 μF, E = 6V , R = 24 Ω

a) l = V/R = 6/24 = 0.25A
b) q = Q(1 – e^-t/RC)
= (8 * 10^–6 * 6) [1 – c^–1] = 48 * 10^–6 * 0.63 = 3.024 * 10^–5
V = Q/C = 3.024 * 10^-5/8 * 10^-6 = 3.78
E = V + iR
⇒ 6 = 3.78 + i24
⇒ i = 0.09 Å
3 years ago
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