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`         An inductor-coil, a capacitor and an AC source of rms voltage 24 V are connected in series. When the frequency of the source is varied, a maximum rms current of 6.0 A is observed. If this inductor coil is connected to a battery of emf 12 V and interna resistance 4.0 Ω, what will be the current?`
3 years ago

Kevin Nash
332 Points
```										Sol. E base rms = 24 V
R = 4 Ω, I base rms = 6 A
R = E/I = 24/6 = 4 Ω
Internal Resistance = 4 Ω
Hence net resistance = 4 + 4 = 8 Ω
∴ Current = 12/8 = 1.5 A

```
3 years ago
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