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`        An inductance of 2.0 H, a capacitance of 18 μF and a resistance of 10 kΩ are connected to an AC source of 20 V with adjustable frequency. (a) What frequency should be chosen to maximize the current in the circuit? (b) What is the value of this maximum current?`
3 years ago

Deepak Patra
474 Points
```										Sol. (a)For current to be maximum in a circuit
X base l = X base c (Resonant Condition)
⇒ WL = 1/WC
⇒W^2 = 1/LC = ½ * 18 *10^-6 = 10^6/36
⇒ W = 10^3/6 ⇒ 2πf = 10^3/6
⇒ f = 1000/6 * 2π = 26.537 Hz = 27 Hz
(b) Maximum Current = E/R (in resonance and)
= 20/10 * 10^3 = 2/10^3 A = 2 mA

```
3 years ago
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