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`         A coil has resistance of 10 Ω and an inductance of 0.4 henry. It is connected to an AC source of 6.5 V, 30/π Hz. Find the average power consumed in the circuit.`
3 years ago

Kevin Nash
332 Points
```										Sol. R = 10 Ω, L = 0.4 Henry
E = 6.5 V, f = 30/π Hz
Z = √R^2 + X base L^2 = √R^2 + (2πfL)^2
Power = V base rms I base rms cos ∅
= 6.5 * 6.5/Z * R/Z = 6.5 *6.5 *10/[√R^2 + (2πfL)^2]^2 = 6.5 *6.5 *10/10^2 +(2π * 30/π  *0.4)^2 = 6.5 *6.5 *10/100 +576 = 0.625 = 5/8 ω

```
3 years ago
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