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Suppose that two identical resistors are placed in parallel with a 12-Volt battery. The overall current in the circuit is 6 amps. Find the resistance of each register??
Hi vinita ,
The total or equivalent resistance of these two parallel resistors is simply the ratio of the battery voltage to the overall current.
That is, RTot = (VTot) / (ITot) = (12 Volts) / (6 Amps) = 2 Ohms.
For resistors in parallel, the overall or total resistance is expressed by the equation
1/RTot = 1/R1 + 1/R2 Substituting 4 Ohms for each of the individual resistances leads to the overall resistance of 2 Ohms.
Since, the potential difference is 12 V and the current in the circuit is 6 Amp, therefore by applying Ohms law the total combined resistance of the two resistors is 2 ohms. Since there are two identical resistors in parallel each resistance is say R Then, 1/R + 1/R =1/2. 2/R = 1/2 Hence, R = 2 ohms.
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