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If a not equal to b but a^2 = 5b-– 3, b^2 = 5a-– 3, then the equation having the roots a/b and b/a is (A) 3x^2 + 19x + 3 = 0 (B) 3x^2+ –19x + 3 = 0 (C) 3x^2 –+19x – 3 = 0 (D) x^2 –+16x + 1 = 0 is

If a not equal to b but a^2 = 5b-– 3, b^2 = 5a-– 3, then the
equation having the roots a/b and b/a is
(A) 3x^2 + 19x + 3 = 0
(B) 3x^2+ –19x + 3 = 0
(C) 3x^2 –+19x – 3 = 0
(D) x^2 –+16x + 1 = 0
 
 
 
is

Grade:10

1 Answers

Nishant Vora IIT Patna
askIITians Faculty 2467 Points
8 years ago
A^2 – 5B+– 3= 0,
B^2 – 5A + 3= 0

So both A and B satisfies x^2 – 5x + 3= 0
So A and B are roots of above eqn
Now from give info just find sum of roots = A/B + B/A
and Product of roots = A/B * B/A = 1

Hence find the eqn

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