a 20 kg block attached to a spring of spring constant 5N/m is released from rest at a the spring at this instant is having an elongation of 1 m the block is allowed to move in smooth horizontal slot with the help of constant force 50 N in the rope the velocity of the block as if reaches B

Question

deepak singh · Answer

Change in ke = wd by spring +wd by external forceWD by spring =- 60NWD by external force = 160NCalculate other things

Shubham Kumar Gupta Ggps · Answer

Work done by spring is -120 and by rope is 160 so 160-120=40 is KENow if we find velocity then it comes out to be v=2m/s

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a 20 kg block attached to a spring of spring constant 5N/m is released from rest at a the spring at this instant is having an elongation of 1 m the block is allowed to move in smooth horizontal slot with the help of constant force 50 N in the rope the velocity of the block as if reaches B

a 20 kg block attached to a spring of spring constant 5N/m is released from rest at a the spring at this instant is having an elongation of 1 m the block is allowed to move in smooth horizontal slot with the help of constant force 50 N in the rope the velocity of the block as if reaches B

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a 20 kg block attached to a spring of spring constant 5N/m is released from rest at a the spring at this instant is having an elongation of 1 m the block is allowed to move in smooth horizontal slot with the help of constant force 50 N in the rope the velocity of the block as if reaches B

a 20 kg block attached to a spring of spring constant 5N/m is released from rest at a the spring at this instant is having an elongation of 1 m the block is allowed to move in smooth horizontal slot with the help of constant force 50 N in the rope the velocity of the block as if reaches B

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