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pranay -askiitians expert Grade: 12
        

 Two moles of Helium gas (γ = 5/3) are initially at temperature 27oC and occupy a volume of 20 litres. The gas is first expanded at constant pressure until the volume is doubled. Then it undergoes an adiabatic change until the temperature returns to its initial value. What are the final volume?


(A)    113.13 × 10–3 m3                                     


(B)    213.13 × 10–3 m3  


(C)    313.13 × 10–3 m3                                   


(D)    13.13 × 10–3 m3 

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

pv = nRT


for first process pressure is kept constant so


v directionally proportional to temp


 Vi/Vf  =  Ti/Tf


 Vf = 2Vi ,  Vi = 20L  & Ti=300k


 so T2 = 600k


now second process is adiabatic so TVr-1 = c


                    Ti/Tf  =  (Vf/Vi)r-1


Ti = 600 ,Tf=300 , Vi=20*2=40L  & r=5/3 so


Vf = 80*21/2 L


    =113.13*10-3 m3

6 years ago
pranay -askiitians expert
44 Points
										

thank you

6 years ago
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