Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
the 50 KG homogeneous smooth sphere rests on the 30 degree incline A and against the smooth vertical wall B.calculate contact forces at A and B.
let the contact force acting on point A be A newtons and acting on point B be B newtons.then by resolving forces along horizontal and vertical directions
A cos 30=mg
A sin 30=B
A=50*9.8/.866=565.81 Newton
B=565.81*.5=282.90 Newton
sorry sir,but diagram is not clear.pls post again
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !