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gowtham raj Grade: Upto college level
        

sir,please help me in solving this question


A 0.1kg mass is suspended frm a wire of negligible mass.the length of wire is 1m and its cross sectional area is 4.9 * 10^-7 m^2.if the mass is pulled a little in the vertically downward direction and released,it performs SHM of angular frequency 140 rad/s.if the young's modulus of the wire is n * 10^9 N/m2, the value of n is....


please explain and solve this integer type question of jee2010.

6 years ago

Answers : (1)

Chetan Mandayam Nayakar
312 Points
										

youngs modulus =Fl/Adl, thus F=490ndl, F=kdl(hooke's law), k=490n,ω=√(k/m), 140=√(4900n),


n=4

6 years ago
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