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gowtham raj Grade: Upto college level
```        sir,please help me in solving this question
A 0.1kg mass is suspended frm a wire of negligible mass.the length of wire is 1m and its cross sectional area is 4.9 * 10^-7 m^2.if the mass is pulled a little in the vertically downward direction and released,it performs SHM of angular frequency 140 rad/s.if the young's modulus of the wire is n * 10^9 N/m2, the value of n is....
please explain and solve this integer type question of jee2010.```
7 years ago

Chetan Mandayam Nayakar
312 Points
```										youngs modulus =Fl/Adl, thus F=490ndl, F=kdl(hooke's law), k=490n,ω=√(k/m), 140=√(4900n),
n=4
```
7 years ago
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