the minimum value of 2 ( x^2-3)^3+27 is 1)2 27 2)2 3)1 4)4

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Nishant Vora · Answer

Nandana · Answer

option 3 : 1 is the answer for this question . let’s see how ! given , 2 ( x^2-3)^3+27 , then 2 ( 0-3)^3+27 = 2^(-27 +27 ) = 2^0 = 1 . so the value of x is ‘0’

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the minimum value of 2 ( x^2-3)^3+27 is 1)2 27 2)2 3)1 4)4

the minimum value of 2⁽^{x^2-3)^3+27 is}

1)2^{27 2)2 3)1 4)4}

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the minimum value of 2 ( x^2-3)^3+27 is 1)2 27 2)2 3)1 4)4

the minimum value of 2(x^2-3)^3+27 is 1)227 2)2 3)1 4)4

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the minimum value of 2⁽^{x^2-3)^3+27 is}

1)2^{27 2)2 3)1 4)4}