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f(x) ={ 6^x + 6^-x } + { 3^x + 3^-x } + 2
Range of { 6^x + 6^-x} = [2,infinity)
Range of { 3^x + 3^-x } = [2, infinity)
Hence min value of f(x) = 2+2+2 = 6
Range = [6, infinity ) .
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