Let Φ(x)= 0 ∫ 3 cos3x dx. The function Φ(x) is increasing in [0, π ] increasing in [0, π/2] decreasing in [0, 2π] decreasing in [-π/2, 3π/2]

Question

Let Φ(x)= 0 ∫ 3 cos3x dx. The function Φ(x) is increasing in [0, π ] increasing in [0, π/2] decreasing in [0, 2π] decreasing in [-π/2, 3π/2]

Abhishek Singh · Answer

dont understand whats the limit of integration?? not written correctly

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Let Φ(x)= 0 ∫ 3 cos3x dx. The function Φ(x) is increasing in [0, π ] increasing in [0, π/2] decreasing in [0, 2π] decreasing in [-π/2, 3π/2]

Let Φ(x)= ₀ ∫³cos3x dx. The function Φ(x) is

increasing in [0, π]

increasing in [0, π/2]

decreasing in [0, 2π]

decreasing in [-π/2, 3π/2]

1 Answers

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Let Φ(x)= 0 ∫ 3 cos3x dx. The function Φ(x) is increasing in [0, π ] increasing in [0, π/2] decreasing in [0, 2π] decreasing in [-π/2, 3π/2]

Let Φ(x)= 0 ∫3 cos3x dx. The function Φ(x) is increasing in [0, π] increasing in [0, π/2] decreasing in [0, 2π] decreasing in [-π/2, 3π/2]

1 Answers

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Let Φ(x)= ₀ ∫³cos3x dx. The function Φ(x) is

increasing in [0, π]

increasing in [0, π/2]

decreasing in [0, 2π]

decreasing in [-π/2, 3π/2]