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sohan singh singh Grade: 12
        




Find the minimum distance between the curves y^2 = x-1 and x^2 = y-1                                   please give detail  solution



 


 

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Amrit pal




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both curve are mirror image to each other about y=x


shortaset distance between these two corve is the segment made by line AB which is perpendicular to both the curve at point A and B respectively


as well as line AB is perpendicular to line y=x ,


i.e  slope of line AB is -1


let a general point A is(t2 ,t22 +1)  and point B is (t12 +1 ,t1)


 slope of curve x2 =y-1 at A is  dy/dx = 2x


                 so slope for perpendicular at point A is -1/2x =-1/2t2


it will be equal to -1


 -1/2t2 =-1


 t2 =1/2




somilerly slope of perpendiculat on y2 =x-1 at point B is  = -2t1


 -2t1 = -1


 t1=1/2




so poins A and B become ( 1/2 ,5/4) and B is (5/4,1/2)


now find the distance between these two point. 


So the minimum distance is (3/4) *√ 2




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Badiuddin



7 years ago
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