MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 320 off
USE CODE: JEE20

				   

Please explain in brief the wavy curve method & also solve this ques..

f(x)=(x-2)²(1-x)(x-3)³(x-4)²/(x+1) ≤ 0 find the value of X.

6 years ago

Share

Answers : (8)

										

Dear neeraj


f(x)=(x-2)²(1-x)(x-3)³(x-4)²/(x+1) ≤ 0


 (x-2)2 (x-3)2(x-4)2   is always positive


at x=2,3,4   (x-2)2 (x-3)2(x-4)2 is  zero 


so x=2,3,4 is a solution  


 


now for  (1-x)(x-3)/(x+1) ≤ 0


  or        (x-1)(x-3)/(x+1) ≥ 0




 




 


 


 


 


7357-2077_7662_untitled.JPG


so silution is [-1,1] and [3,∞) 


 


so final solution   [-1,1] and [3,∞)  and 2


Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin

6 years ago
										

(-1,1] U [3,∞) U {2}      Smile

3 years ago
										

sir,i am unable to understand the solution for the question.please explain clearly

3 years ago
										

-(x-2)2 (x-1)(x-3)3 (x-4)2 /(x+1)≤0


(x-2)2 (x-1)(x-3)3 (x-4)2 /(x+1)≥0


equate every linear factor by 0,


x=1,2,3,4,-1


by ploting the values nof x on no line we get,


x Ε (-∞,-1]υ[1,2]υ[3,4]υ[4,∞)


........

3 years ago
										

HERE, ON WHAT BASIS IS 2 PLACED IN ANSWER.


AND HOW CLOSE AND OPEN BRACKETS ARE ADDED.


PLEASE HELP ME. FAST.


 


f(x)=(x-2)²(1-x)(x-3)³(x-4)²/(x+1) ≤ 0


 (x-2)2 (x-3)2(x-4)2   is always positive


at x=2,3,4   (x-2)2 (x-3)2(x-4)2 is  zero 


so x=2,3,4 is a solution   


now for  (1-x)(x-3)/(x+1) ≤ 0


  or         (x-1)(x-3)/(x+1) ≥ 0


 7357-2077_7662_untitled.JPG


ans:   (-1,1] U [3,∞) U {2}


HERE, ON WHAT BASIS IS 2 PLACED IN ANSWER.


AND HOW CLOSE AND OPEN BRACKETS ARE ADDED.


PLEASE HELP ME. FAST.

2 years ago
										

explain to me: why does the wavy curve method hold?  what is the actual idea behind it?

2 years ago
										I can answer your question very well, if you want me to; now.

Anukul Sangwan
Class 10
FIITJEE South Delhi
2 years ago
										xE(-8,-1)U[1.2]U[3,8]
										
one year ago

Post Your Answer

Evaluate the following
 
 
 
jagdish singh singh 3 months ago
Let f : [a, b] → R be continuous on [a, b] and differentiable on (a, b). Suppose that f(a) = a and f(b) = b. Show that there is c ∈ (a, b) such that f′(c) = 1. Further, show that there are...
 
 
BY LMVT(Lagrange mean value theorem) Apply theorem in at points (a,f(a)) & (b,f(b)) This prove the first part that there exist a point c between a & b such that SECOND PART now break the...
 
Aakash 6 months ago
 
My answer was exactly the same as of Akash. But you disapproved my answer.
 
Anoopam Mishra 6 months ago
 
This is not fair!!!!!
 
Anoopam Mishra 6 months ago
How will u differentiate this Y= C1(e^3x) + C2(e^2x) + C3(e^x) ?
 
 
If C1, C2 & C3 are constants then by applying chain rule, the derivative of the given eqn. will be dy/dx= 3C1(e^3x) + 2C2(e^2x) + C3(e^x)
 
Aryan Shukla 3 months ago
sir please solve this question
 
 
13 guests in the party can be divided inti 2 groups of 8and5 in 13c8 or 13c5 . The first group of 8 guests can be arranged around at one table in 7! ways. The second group of 5 guests can...
 
PRAPULPODISHETTI 5 months ago
 
We can arrange the guests 15,56,75,520 in this ways. its equals to (13!/40)
 
PRAPULPODISHETTI 5 months ago
 
13!/40 value is equlas to 15,56,75,520.
 
PRAPULPODISHETTI 5 months ago
(a+b)^2
 
 
a^2+2ab+b^2
 
venky 5 months ago
 
a+ b ) 2 a b a2 ab ab b2  The above diagram represents – a+ b is a line and the square are is a 2 + b2 +2ab Hence proved - (a+ b ) 2 = a 2 + b2 +2ab
 
Prabhakar ch 7 days ago
 
a^2 +2ab+b^2
 
SEELA YUVARAJU 5 months ago
How to find root of 8+3i in complex numbers???????????????????????
 
 
Let x+iy=root of 8+3i (x+iy) 2 =8+3i x 2 -y 2 +2xyi=8+3i On comparing, x2-y2=8 and 2xy=3 ie x=3/(2y) 9/(4y 2 ) – y 2 =8 Solve and get the values of x and y z=x+iy
 
Amogh Dasture 12 days ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,000 off
USE CODE: JEE20

Get extra R 320 off
USE CODE: JEE20

More Questions On Differential Calculus

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details