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`        Find the derivative of                    y = arcsinh(1-x/1+x)derivatives`
7 years ago

23 Points
```										Dear Satyam,
we know that d/dx(arcsinh x) = 1/√(x2+1)
So here in place of x we have (1-x/1+x)
And d/dx(1-x/1+x)= [ (1+x) d/dx(1-x) - (1-x) d/dx(1+x) ] / (1+x)2
= [ (1+x) *(-1) - (1-x) *1 ] / (1+x)2
= -2/ (1+x)2
now dy/dx = 1/ √((1-x/1+x)2+1) *  d/dx(1-x/1+x)
=[ (1+x)/√2(x2+1) ] *  -2/ (1+x)2
= -√2/ √(x2+1)*(1+x)

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7 years ago
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