Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        Differentiate tan−1   [ (1+x2)1/2 - (1-x2)1/2 ]  w.r.t x ?

(1+x2)1/2 + (1-x2)1/2
8 years ago

Pankaj
131 Points
										I am not able to interpret your query. Please write down the problem clearly so that I can provide you the meaningful answer.Thanks & RegardsPankaj SinghaskIITians Faculty

3 years ago
Arun Kumar
IIT Delhi
256 Points
										Hello Student,$\\\frac{d}{du}\left(\arctan \left(u\right)\right) \\\frac{1}{u^2+1}x\left(\frac{1}{\sqrt{x^2+1}}+\frac{1}{\sqrt{1-x^2}}\right) \\u=\sqrt{1+x^2}-\sqrt{1-x^2} \\=\frac{1}{\left(\sqrt{1+x^2}-\sqrt{1-x^2}\right)^2+1}x\left(\frac{1}{\sqrt{x^2+1}}+\frac{1}{\sqrt{1-x^2}}\right) \\=\frac{x\left(\sqrt{1-x^2}+\sqrt{x^2+1}\right)}{2x^4+3\sqrt{1-x^4}-2}$Thanks & RegardsArun KumarBtech, IIT DelhiAskiitians Faculty

3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Differential Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details