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```				   (1-x2)(1-y)dx=xy(1+y)dy
```

6 years ago

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```										Dear upendra
(1-x2)(1-y)dx=xy(1+y)dy
seperate term
(1-x2)/x dx=y(1+y)/(1-y)  dy
(1/x  -x) dx={-(y+2)  +2/(1-y) }dy
now integrate
lnx -x2/2  =-(y+2)2/2  +-2ln|1-y|   +c

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6 years ago

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