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sindhuja P Grade: 11
```        Lt      [1/x1/ln(e^x-1)+(1/x)sinx-xlogx]  (x>0,and [.] denotes
x→0                                                        greatest integer
function)```
8 years ago

## Answers : (1)

147 Points
```										Dear paidepelly
solve each part individually
first part
Lt x→0     1/x1/ln(e^x-1)

eLt x→0 -(ln x)/ln(ex-1)
use L hospital rule and find limit
=1/e

for second part
Lt x→0(1/x)sinx
e Lt x→0sin x ln(1/x)
use L hospital rule and find limit
=1
for third part
Lt x→0-xlogx  =0
Now add all three limit
1/e +1+0
=.367 +1+0 =1.367
so [1.367] =1 answer

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```
8 years ago
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