im little weak in differential calculus....in exam im not sure if i could solve question or not....i dont get where to start in spite of having practice...what should i do?

2 years ago

Share

Answers : (1)

                                        

Hi Shruti,


Try to work hard on thise questions in these days


Try to take help from some teachers who can solve your doubts on that particular topic,


Work hard on 3 things, Basics, Doubts and Speed


Hope that can help you


Regards

2 years ago

Post Your Answer

More Questions On Differential Calculus

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
Find d/dx tan -1 √1+sinx/1-sins; 0
 
 
tan -1 √1+sinx/1-sinsx = tan -1 √(cos 2 x/2 + sin 2 x/2 + 2*sinx/2*cosx/2)/(cos 2 x/2 + sin 2 x/2 – 2*sinx/2*cosx/2) =tan -1 √(cosx/2 + sinx/2) 2 /(cos x/2 – sin x/2) 2 = tan -1 (cosx/2 +...
 
Y RAJYALAKSHMI 5 months ago
x=a cos( theta) + b sin(theta) y=a sin(theta) – b cos( theta) prove that y*y2-x*y1+y=0
 
 
Ans: Hello Student, Please find answer to your question below Differentiate Differentiate
  img
Jitender Singh 6 months ago
hey image attached please tell the method which is used in solution …..please sir .maam …..please anyone …...
 
 
Ans: Hello student, Please find the answer to your question below [] is greatest integer function. Now looking at the problem in hand There are total 100 term in L out of which 25 terms are...
  img
Jitender Singh 4 months ago
show that (a-b) is a factor of (a+b) 3 - (a-b) 3 -8ab 2
 
 
Hello Student, Please find the trick to solve the question define a polynomial in 'a' like this f(a)= (a+b)^3- (a-b)^3-8ab^2 Now check the value of f(b)= (b+b)^3- (b-b)^3-8b*b^2 = 0...
  img
Nishant Vora 3 months ago
evaluate ∫ (sqrt(x)( ax^2 + bx + c)) dx
 
 
∫ (sqrt(x)( ax^2 + bx + c)dx =​∫ (x^1/2(ax^2 +bx +c)dx =​∫ (ax^5/2 +bx^3/2 +cx^1/2)dx =2​ax^7/2 /7 +2bx^5/2 /5 +2cx^3/2 /3 +K {we know that​∫x^ndx =(x^(n+1) /(n+1)} Here K is...
  img
Sunil Raikwar 5 months ago
 
make ax 2 +bx+c in to form of a((x-b/2) 2 +(c -b 2 /4)). then put (x-b/2)=(c-b 2 /4)^.5*tany. then integrate it. simple
 
Karthick vel 5 months ago
what is k in bisector of the angle between two vectors (as given in ur study material)???
 
 
When two vector amplitides are given at some phase difference, then resultant of these can be find out using Resultant equation, in which the phase angle is the phase difference between that...
  img
Saurabh Kumar 3 months ago
View all Questions »