MY CART (5)

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price:

There are no items in this cart.
Continue Shopping
                   

im little weak in differential calculus....in exam im not sure if i could solve question or not....i dont get where to start in spite of having practice...what should i do?

3 years ago

Share

Answers : (1)

                                        

Hi Shruti,


Try to work hard on thise questions in these days


Try to take help from some teachers who can solve your doubts on that particular topic,


Work hard on 3 things, Basics, Doubts and Speed


Hope that can help you


Regards

3 years ago

Post Your Answer

More Questions On Differential Calculus

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
limit[sinx/x] as x tends to 0 where[.] is gif
 
 
first of all u must know that sinx/x now according to ur question limit[sinx/x] as x tends to 0 will be equal to zero bcoz gif of any nimber less than 1 will be 0 so value of limit is 0...
 
ng29 21 days ago
 
the value of lt(x->0)sinx/x is equeal to 1 from the left side this meant that the value might be 0.9999999999999 and [ 0.9999 ] = 0 therefore [sinx/x] =0
 
akshat 18 days ago
 
sinx/x is less than 1 tanx/x is greater than 1 it was missed in prev answer
 
ng29 21 days ago
Value of x in the following –
 
 
Image is attached
 
Drake 11 months ago
Please prove …..and also give explanation sir please
 
 
Ans: Thanks & Regards Jitender Singh IIT Delhi askIITians Faculty
  img
Jitender Singh 10 months ago
 
Sir but what is answer
 
milind 10 months ago
If a+b=c, prove that cos^2 a+cos^2b+cos^2c =1+2cosacosbcosc
 
 
cos^2a +cos^2b+cos^2c= (1+cos2a)/2+(1+cos2b)/2+cos^2c =1+(1/2)*(2cos(a+b)cos(a-b) +cos^2c (since a+b+c = 0) =1 + cos(-c)cos(a-b)+cos^2c (since cos(-a) = cosa) =1+cos(c)cos(a-b)+cos^2c...
 
Y RAJYALAKSHMI 10 months ago
View all Questions »