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				   If f(x) is a polynomial function which satisfy the relation (f(x))2 f"(x)=(f"(x))3 f'(x), f'(0)=f'(1)=f'(-1)=0,f(0)=4, f(±1)=3, then f"(i) (where i=√7) is equal to


4 years ago

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										Ans:$f'(0) = f'(-1) = f'(1) = 0$$\Rightarrow f'(x) = ax(x-1)(x+1), a = constant$$\int df(x) = \int ax(x-1)(x+1)dx$$f(x) = a(\frac{x^{4}}{4}-\frac{x^{2}}{2}) + c, c = constant$$f(0) = a(\frac{0^{4}}{4}-\frac{0^{2}}{2}) + c = 4$$\Rightarrow c = 4$$f(\pm 1) = a(\frac{(\pm 1)^{4}}{4}-\frac{(\pm 1)^{2}}{2}) + 4 = 3$$\frac{-a}{4} = -1$$a = 4$$f(x) = x^{4}-2x^{2}+4$$f'(x) = 4x^{3}-4x$$f''(x) = 12x^{2}-4$$f''(\sqrt{7}) = 12(\sqrt{7})^{2}-4 = 80$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

one year ago

what is the lenght of subtangent in the term of differential quotients of any general curve...

Let tangent and normal to a parabola at a point P(x1,y1) be extended to meet the axis of the parabola at N and T respectively. PT is termed the length of the tangent. PN is termed the length...

 Harsh Patodia 3 months ago
Please provide solution to the third part...

Hii just find out the values of (n+2)a n+2 na n a n+1 Find out the values of these and you will get the nanswer.

 Sourabh Singh one month ago
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 N JYOTHEESWAR 4 months ago

hi chethan Have someone type in any number between 1 and 900 into the calculator without letting you know what it is. (Actually, this trick will work for numbers greater ...

 manichandra 4 months ago

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 mohan 4 months ago
tan75

TAN 75 =TAN ( 45 + 30 ) =(TAN 45 + TAN 30 ) / ( 1-TAN 45 TAN 30 ) =(1+1÷√3)÷(1−(1×1÷√3)) =3.732050808 ANSWER IS TAN75 = 3.732050808. IF YOU LIKE THIS ANSWER PLZ APPROVE IT.

 SAI SARDAR 8 months ago

PLZ APPROVE

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solve this vectors of OA=I+J+K ; AB=3I-2J+K; BC=I+2J-2K and CD =2I+J+3K FIND OD VECTOR

p { margin-bottom: 0.25cm; line-height: 120%; } GIVEN VECTORS OA=I+J+K;AB=3I-2J+K;BC=I+2J-2K AND CD=2I+J+3K WE KNOW THAT VECTOR AB =OB-OA 3I-2J+K= OB-( I+J+K) OB=4I-J+2K SIMILARLY BC =OC-OB ...

 PASUPULETI GURU MAHESH 2 months ago
cot^2a + cosec^2a

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 VIKRAM ENIMIREDDY 8 months ago

CotA

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