1800 2000 838

CART 0

• 0

MY CART (5)

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping

X

X

                   If f(x) is a polynomial function which satisfy the relation (f(x))2 f"(x)=(f"(x))3 f'(x), f'(0)=f'(1)=f'(-1)=0,f(0)=4, f(±1)=3, then f"(i) (where i=√7) is equal to


3 years ago

Share

                                        Ans:$f'(0) = f'(-1) = f'(1) = 0$$\Rightarrow f'(x) = ax(x-1)(x+1), a = constant$$\int df(x) = \int ax(x-1)(x+1)dx$$f(x) = a(\frac{x^{4}}{4}-\frac{x^{2}}{2}) + c, c = constant$$f(0) = a(\frac{0^{4}}{4}-\frac{0^{2}}{2}) + c = 4$$\Rightarrow c = 4$$f(\pm 1) = a(\frac{(\pm 1)^{4}}{4}-\frac{(\pm 1)^{2}}{2}) + 4 = 3$$\frac{-a}{4} = -1$$a = 4$$f(x) = x^{4}-2x^{2}+4$$f'(x) = 4x^{3}-4x$$f''(x) = 12x^{2}-4$$f''(\sqrt{7}) = 12(\sqrt{7})^{2}-4 = 80$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

one year ago

More Questions On Differential Calculus

Post Question

Vouchers
To Win!!!
3y = ( log x ) ^2 Is y a function of x ? x belongs to R , y belongs to R.

no it is not a function because at domain and x and y both is real numbers but if we put x =0 then there is no value of y will be corresponding to that x bcoz log(0) is not defined approve...

 ng29 3 months ago

THE VALUE OF X WOULD BE DEFINED WHEN X [R + ] ITH VALUE OF Y AIN’T BE DETERMINED SO NO FUNCTION HENCE NO QUESTION OF CONTINUITY OR DISCONTINUITY APPROVE IF USEFUL

I think its a function but just discontinuous.

 noneool 3 months ago
what is l’hospital rule?

l’hospital rule is used to calculate the value of the funcions having limits attached to them there first of all we get the 0/0 form and then we diffrentiate the numerator and denominator...

The above statement can be extended to any indeteminant forms such as those with infinity or division by 0.Just differentiate the nuemerator and denominator until you can easily apply the...

 IVIN ZACHARIA THOMAS 2 months ago
can someone tell me where is monotonicity part in the book M.L. Khanna. I’m unable to solve questions of monotonicity.

Monotonocity part in Ml khanna is in chapters like derivatives,differentiations etc

 Charchit Tailong 4 days ago
how many 5 letter words can be formed from letters of INDEPENDENT

11 LETTERS.3N’S 3E’S 2D’S 1P 1I 1T. NO.OF 5 LETTER WORDS; CASE 1;OUT OF 5 3ARE ALIKE AND 2 ARE DIFFERENT 2C1.5C2.5!/3!=400 CASE 2;OUT OF 5 3 ARE ALIKE OF ONE KIND AND 2 ARE ALIKE OF OTHER...

 yaswanth 7 months ago

11 LETTERS.3N’S 3E’S 2D’S 1P 1I 1T. NO.OF 5 LETTER WORDS; CASE 1;OUT OF 5 3ARE ALIKE AND 2 ARE DIFFERENT 2C1.5C2.5!/3!=400 CASE 2;OUT OF 5 3 ARE ALIKE OF ONE KIND AND 2 ARE ALIKE OF OTHER...

 yaswanth 7 months ago

11 LETTERS.3N’S 3E’S 2D’S 1P 1I 1T. NO.OF 5 LETTER WORDS; CASE 1;OUT OF 5 3ARE ALIKE AND 2 ARE DIFFERENT 2C1.5C2.5!/3!=400 CASE 2;OUT OF 5 3 ARE ALIKE OF ONE KIND AND 2 ARE ALIKE OF OTHER...

 yaswanth 7 months ago
tanx/x plllllllllz