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whats the sum of series:

1^5*2^7/1! + 2^5*3^7/2! + 3^5*4^7/3! + 4^5*5^7/4! +......................infinite....

3 years ago


Answers : (1)

                                        Dear student,
The general term of the series can be given by:
T_{n}=\frac{n^{5}\left ( n+1 \right )^{7}}{n!}

So, the required sum can be found as:
S_{n}=\sum_{1}^{\infty}T_{n}=\sum_{1}^{\infty}\frac{n^{5}\left ( n+1 \right )^{7}}{n!}
Using the standard formulae, the required sum can be found.
one year ago

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